#155easyStatistics

Exponential Waiting Time

Time Limit: 2sMemory: 256MB

Problem

Given an exponential distribution with rate parameter lambda and a time value t, compute the probability that the waiting time exceeds t:

$P(X > t) \text{ where } X \sim \text{Exp}(\lambda)$

Two space-separated floating-point numbers: lambda and t.

A single floating-point number to 6 decimal places representing $P(X > t)$ .

Example 1

Input(Two space-separated floating-point numbers: lambda and t.)

1 1

Output

0.367879

P(X > 1) = e^(-1*1) = e^(-1) = 0.367879.

Example 2

Input(Two space-separated floating-point numbers: lambda and t.)

0.5 2

Output

0.367879

P(X > 2) = e^(-0.5*2) = e^(-1) = 0.367879.

Loading interactive editor…